Question

When the son will be as old as his father today, the sum of
their ages then will be 126. When the father was as old as his
son is today, the sum of their ages then was 38. Find their
present ages.​

Answer 1

Answer:

Let the present ages of son and his father are x and y respectively.

The difference of their ages is- (y-x).

Hence, it will take (y-x) more years for son to reach his father's present age. After (y-x) years sum of their ages will be - (which is given 126)

.

.

[ x + (y-x) ] + [ y + (y-x) ] = 126

.

.

3y-x = 126. ........ eq-1

Similarly (y-x) before father's age was equal his son's present age. (y-x) years before sum of their age was- ( which is given 38)--

[ x - (y-x) ] + [ y - (y-x) ] = 38

.

.

3x - y = 38................. eq-2

by multiplying eq-2 with 3 and then adding to the eq-1

3y - x = 126

9x - 3y = 114

--------------------

8x = 240

x = 30

Putting x =30 to the eq-2

Y= 52

So son's age is 30 years and father's age is 52 years