Question

When the son will be as old as his father today, the sum of their ages then will be 126. When the father was as old as his son is today, the sum of their ages then was 38. Then find their present ages.​

Answer 1

Answer:

THE ANSWERIS 63 MAYBE. . . . . . .

Answer 2

Let son's current age is x and father 's current age is y.

Now,where does the (y−x) term come from?

(y−x=40−10=30 years).

[Father's new age] + [Son's new age] =126

[y+(y−x)]+[(x+(y−x))]=126

⇒2y−x+y=126

∴3y−x=126 (1)

[Father 's previous age] + [Son 's previous age]=38

[y−(y−x)]+[x−(y−x)]=38

⇒x+x−y+x=38

⇒3x−y=38

∴y=3x−38(2)

Now sub equation(2) into equation(1)

⇒3(3x−38)−x=126

⇒9x−114−x=126

⇒8x=240

∴x=30

Now y=3x−38

⇒y=3(30)−38

∴y=52

The son is 30 years old, and the father is 52 years old.