Math, asked by Da2seprekshaa, 1 year ago


When the son will be as old as the father today their ages will add up to 126 years.When the father was old as the son is today,their ages add upto 38 years,Find their present ages.

Answers

Answered by tejasmba
18
Let us assume, father's present age is x years and son's present age is y years.

When the son will be as old as the father today, son's age will be his farther's age = x years.

Thus, the sum of the ages = x + x = 126
Therefore, x = 126/2 = 63 years

Similarly, 
When the father was old as the son is today, father's age will be his son's age = y years.

Thus, the sum of the ages = y + y = 38
Therefore, y = 38/2 = 19 years.

The present age of father is 63 years and present age of son is 19 years.
Answered by stevegsaiju
0

Answer:

Age of Son = 30 years old, Age of Father = 52 years old

Hint: The Father and Son both age accordingly.

Example: Son = 15yrs, Father = 40yrs. If Son becomes 17 ( 15+2 ) then Father becomes 42 ( 40+2 )

Step-by-step explanation:

Let,

     Son's current age = x

     Father's current age = y

     Difference between Age of Father and Son = x - y

Case 1: When Son become Father's current Age (and the Father becomes the number of years taken by the Son to reach the Fathers current Age, i.e., The difference between their ages + Father's Current Age)

[Father's new age] + [Son's new age] = 126

[ y + (y−x) ] + [ x + (y−x) ] = 126

⇒ (2y−x) + (y) = 126

∴ 3y−x = 126   -----> (1)

Case 2: When Father become Son's current Age (and the Son becomes the number of years deducted by the Father to reach the Son's current Age, i.e., The difference between their ages - Son's Current Age)

[Father's previous age] + [Son's previous age] = 38

[ y − (y−x) ] + [ x − (y−x) ] = 38

⇒ (x+x) + (−y+x) = 38

⇒ ( −y+3x = 38 ) x 3 (For fulfilling Elimination Method Criteria)

∴ −3y+9x = 114   -----> (2)

Using Elimination Method,

          −3y + 9x = 114   -----> (2)

            3y − x   = 126  -----> (1)

(2)-(1)⇒         8x = 240

                     ∴ x = 240/8 = 30 yrs

Put x = 30 in eqn (1),

3y − x   = 126

3y − 30   = 126

3y = 126 + 30 = 156

y = 156/3 = 52 yrs

The son is 30 yrs old and the father is 52 yrs old.

Similar questions