When the speed of a particle is doubled, the ratio of its kinetic energy to its momentum will be
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8
speed be v... double spped be 2v
KE=½m2v²......i
p=m2v.......ii
dividing eq i by ii we get
v/2
KE=½m2v²......i
p=m2v.......ii
dividing eq i by ii we get
v/2
Answered by
5
then the ratio is equal to v:1
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