when the speed of the ball is doubled what happen to kinetic energy ?
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K.E of ball=1/2mv²
when speed or velocity is doubled i.e. 2v
therefore new K.E=1/2m(2v)²
=4 × 1/2mv²
Hence, the new K.E becomes 4 times the earlier K.E.
when speed or velocity is doubled i.e. 2v
therefore new K.E=1/2m(2v)²
=4 × 1/2mv²
Hence, the new K.E becomes 4 times the earlier K.E.
syedaleemuddin:
thanks for the wrte answer
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answer in the above attachment
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