When the sum of a 2-digit number ab and number obtained by reversing the digits is
divided by (a + b), then quotient is
(a) ab
(b) 9 (c) 11
(d) None of these
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Answer:
The answer to your Question is:(c)11
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Step-by-step explanation:
The value of number ab is=10a+b
the value of no. formed by reversing the number ab is=10b+a
the sum of number ab and ba is=(10a+b)+(10b+a)
= 11a+11b
=11(a+b)
The quotient when (ab+ba) is devided by (a+b) is
=[11(a+b)]/(a+b)
=11
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