when the sum of area and perimeter of a square is 192 if side of the square is taken as x. a) what is the area .b) find perimeter of square
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Let the length of the rectangle =l cm and breadth =b cm.
Area of the rectangle =l×b=192cm2 ....(1)
Perimeter of the rectangle =2(l+b)=56 cm
⇒l+b=28 or l=28−b ....(2)
Putting the value of l in equation (1), we get
(28−b)×b=192
28b−b2=192
b2−28b+192=0
(b−16)(b−12)=0
=>b=16 or 12 cm
Substituting the value of b =16 cm in equation (1), we get
l×16=192
⇒l=12 cm
Similarly, if b =12 cm, l=16 cm.
Dimension of the rectangle are 12 cm and 16 cm
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