Math, asked by prbm2008, 2 months ago

when the sum of cubes (17^3+19^3+21^3+23^3) is divided by 83 the remainder so obtained is:
a.0
b.1
c.3
d.8​

Answers

Answered by 28208
0

Answer:

c

Step-by-step explanation:

The answer is 3, it is simple.

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