When the sun is at an angle of elevation 30° the shadow of a tree is 30m.What is the height of the tree?
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0
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Answer:
AB is the tower , BC is the length of the shadow of tower when altitude is 30
∘
i.e the angle of elevation of the top of the tower from the tip of the shadow is 30
∘
and DB is the length of the shadow, when the angle of elevation is 60
∘
Given, BC = 30 m
In △ABC
tan30
∘
=
BC
AB
⇒
3
1
=
30
AB
⇒AB=
3
30
=10
3
m
Now,
In △ABD
tan60
∘
=
BD
AB
⇒
3
=
BD
10
3
⇒BD=10m
Option C is correct
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