Math, asked by janyben1998, 5 hours ago

When the sun is at an elevation of 30degree the length of the shadow of a tree is 15m.what is height of the tree?

Answers

Answered by anushikumari1122

Answer:

Let AB be the tower of height 300 ft.

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30=

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BC

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 =

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 = BC

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 = BC300

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 = BC300 ⇒BC=300

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 = BC300 ⇒BC=300 3

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 = BC300 ⇒BC=300 3 ft

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 = BC300 ⇒BC=300 3 ftSo, length of the shadow of the tower is 300

Let AB be the tower of height 300 ft.Let BC be the length of the shadow of the tower such that ∠ACB=30 o Now,tan30= BCAB ⇒ 3 1 = BC300 ⇒BC=300 3 ftSo, length of the shadow of the tower is 300 3 ft

Answered by sathwikkankanala74

Step-by-step explanation:

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