Question

when the sun is at an elevation of 40°,the length of a shadow of a tree is 18 meters. What is the height of the tree.​

Answer 1

Answer:

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Given :

Angle of elevation = 40°

Length of shadow = 18 m.

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Let the required triangle be Δ ABC.

∴ Angle of elevation = ∠ ABC=40°

Length of shadow = AB = 18 m

Height of tree be AC.

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In right Δ BAC,

AC = AB × tan 40°

➟ AC = 18 × tan 40° (tan 40° = 0.839)

➟ AC = 18 × 0.839 = 15.102 m = 15.1 m

So, Height of tree is 15.1 metre.

Answer 2

Answer:

Given :

Angle of elevation = 40°

Length of shadow = 18 m.

Let the required triangle be Δ ABC.

∴ Angle of elevation = ∠ ABC=40°

Length of shadow = AB = 18 m

Height of tree be AC.

In right Δ BAC,

AC = AB × tan 40°

➟ AC = 18 × tan 40° (tan 40° = 0.839)

➟ AC = 18 × 0.839 = 15.102 m = 15.1 m

So, Height of tree is 15.1 metre.

Step-by-step explanation:

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