Question

When the switch in the circuit is closed the reading on voltmeter 1 is 30V and that on voltmeter 2 is
10V. Determine the reading on the ammeter and the value of resistor Rx.
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Answer 1

Answer:

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Explanation:

When the switch in the following circuit is closed the reading on voltmeter 1 is 30V and that on voltmeter 2 is ... Determine the reading on the ammeter and the value of resistor Rx. 52 R 2.

Answer 2

Answer:

Therefore, reading on ammeter is 4 A and value of resistor $R_{X}$ = 2.5 Ω.

Explanation:

What is potential difference between two points?

The amount of effort required to move a unit charge from one position to another is the definition of potential difference between any two points.

According to diagram,

V₁ = 30 V

V₂ = 10 V

R = 5 Ω = ( V₁ - V₂ ) = ( 30 - 10 ) V  = 20 V

According to Ohm's law

Current in  5 Ω resistor i.e. Reading on Ammeter = $\frac{V}{R}$ = $\frac{20}{5}$ = 4 A

Total resistance, $R_{T} = \frac{V_{T} }{I}$ = $\frac{30}{4}$ = 7.5 Ω

Hence, $R_{X}$ = ( 7.5 - 5 ) Ω  = 2.5 Ω

Conclusion

So, reading on ammeter is 4 A and value of resistor $R_{X}$ = 2.5 Ω.

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