Question

When the temperature of an ideal gas is increased by 600 K, the velocity of sound in the gas becomes √3 times the initial velocity in it. The initial temperature of the gas is .............. .
(a) -73 °C
(b) 27 °C
(c) 127 °C
(d) 327 °C

Answer 1

Answer: 27°C

Explanation:

Answer 2

Answer:

27 ° C

Explanation:

We have been given that  ,

Temperature of an ideal gas is increased by 600 K

Velocity of sound in the gas becomes √3 times

Now ,

Initial temperature in ideal gas is  T₁ =  T K

Temperature of an ideal gas is increased by T ₂ = T + 600 K

Velocity in gas  V₁

Velocity of sound is  $V2 = V \sqrt{3}$

We know that

\dfrac{V1}{V2 } }  = \sqrt{\dfrac{T1}{T2} \\\\

[/tex}\\[/tex]\dfrac{V}{V\sqrt{3} } } = \sqrt{\dfrac{T}{T + 600} \\ [/tex}\\[/tex]

T = 300

T = 300 - 273

T = 27 ° C

Correct answer is Initial temperature in ideal gas is  T₁  = 27 ° C