Chemistry, asked by nischaynokhwal99, 5 months ago

When the temperature of the reaction increases from
30OK to 320K, the rate of reaction becomes four
times of the initial rate. The activation energy (in kJ/
mole) of the reactants will be (where R = 8.314 JK

(1) 50.3
(2) 553
(4) 5.53
3) 55.

Answers

Answered by sheshappad
2

Answer:

55.3 is the correct answer

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