Question

When the value of the evacuated bottle is opened, atmospheric air rushes into it. If the atmospheric pressure is 101.325 kPa and 0.6m3 of air (measured at atmospheric conditions) enters into the bottle, calculate the workdone by the air​

Answer 1

Answer:

If you consider the bottle as the system then work done is not zero. If you consider the bottle along with the environment then it is a case of free expansion with zero work

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Answer 2

Answer:

60.795 kJ

Explanation:

W = P⋅dV

W = 101.325 × (0.6 – 0) = 60.795 kJ