Question

When the zero of a pokynomial 2xsq-7x +k areReciprocal of eacj other then the value of k

Answer 1

Answer:

k = 2

Step-by-step explanation:

==: 2x² - 7x + k = 0

Zeroes are reciprocal to each other

Product of zeroes = α * β = a * 1/α = 1

But , Product of zeroes = c/a = k/2

==: k/2 = 1

==: k = 2

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