when there is a decrease of 10 km/hr in the usual speed of a train.It takes four 1 upon 2 hours more to cover 900 km distance.find the usual speed of the train
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let the original speed be x km/hr
decreased speed be(x-10)km/hr
time= 9/2hrs
ACC to question
900/x - 900/(x-10) = 9/ 2
x= 50 km/hr ( original speed )
decreased speed be(x-10)km/hr
time= 9/2hrs
ACC to question
900/x - 900/(x-10) = 9/ 2
x= 50 km/hr ( original speed )
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I hope this helps.....
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