when three 10 ohm resistor are connected in star across a 400 volt,3 phase supply what power should be have of resistors
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Answer:
Answer
Given,
R
1
=5Ω, R
2
=3Ω, R
3
=2Ω, V=10 Volt
Effective resistance of series combination.
R
s
=R
1
+R
2
+R
3
=10Ω
Now,
Current in Circuit I=I=
R
s
V
=
10
10
=1A
Voltage drop across R
1
, V
1
=IR
1
=1×5=5V
Voltage drop across R
2
, V
2
=IR
2
=1×3=3V
Voltage drop across R
3
, V
3
=IR
3
=1×2=2V
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