Math, asked by Julyin308, 5 months ago

When three brands of juices are mixed in the ratio of 3 : 4 : 5 and 4: 5:6, the cost
price of the two piece mixtures comes out to be Rs. 20 per litre and Rs. 25 per litre
respectively. Find the cost price of a litre of mixture of juices in which the three brands
of original juices are mixed in the ratio of 6:7:8​

Answers

Answered by amitnrw
2

Given : three brands of juices are mixed in the ratio of 3 : 4 : 5 and 4: 5:6, the cost  price of the two  mixtures comes out to be Rs. 20 per litre and Rs. 25 per litre  respectively.

To Find : the cost price of a litre of mixture of juices in which the three brands  of original juices are mixed in the ratio of 6:7:8​

Solution:

Cost of juice per litre are A , B & C respectively

ratio of 3 : 4 : 5   then mixture  Rs. 20 per litre

3 + 4 + 5 = 12 Litre  

12 * 20 = 240 Rs

3A  + 4B  + 5C  = 240   Eq1

ratio of 4 : 5 : 6   then mixture  Rs. 25per litre

4 + 5 + 6 = 15 Litre  

15 * 25 = 375 Rs

4A  + 5B  + 6C  =375     Eq2

Eq2 - Eq1

=> A + B + C  = 135

=> 2A + 2B + 2C = 270

4A  + 5B  + 6C  =375

2A + 2B + 2C = 270

Adding Both

6A + 7B + 8C  = 645

6 + 7 + 8  = 21  

645/21 = 30.7

cost price of a litre of mixture of juices in which the three brands

of original juices are mixed in the ratio of 6:7:8​  is    30.7  

But Actually Data is wrong

as 3A  + 4B  + 5C  = 240

   2A + 2B + 2C = 270

=> A + 2B + 3C = - 30   ( which is not possible ) as Cost can not be negative

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