when three coins are tossed simultaneously find the probability of getting atleast two tails
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Number of possible outcomes=8
{(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)}. in which atleast two tails means 4 times know..so probability is 4/8=1/2
{(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)}. in which atleast two tails means 4 times know..so probability is 4/8=1/2
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Hello! mate required answer is as follow:-
same space is- HHH HHT HTH HTT
THH THT TTH TTT
According to question:
Probability(at least two tails)=4/8=1/2.
if helpful please mark as a brainliest answer.
same space is- HHH HHT HTH HTT
THH THT TTH TTT
According to question:
Probability(at least two tails)=4/8=1/2.
if helpful please mark as a brainliest answer.
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