Question

when three coins are tossed simultaneously find the probability of getting at least 2 tails​

Answer 1

Answer:

Step-by-step explanation:

A coin has two sides head (H) and tail(T).

If we toss three coins then the possible outcomes are as follows:

(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)

SOLUTION:

Number of possible outcomes=8

{(H,H,H) (H,H,T),(H,T,H),(T,H,H),(H,T,T),(T,H,T),(T,T,H) & (T,T,T)}

Number of favourable outcomes (at least 2heads)=4

Probability (at least 2headd)= Number of favourable outcomes/total number of outcomes

Probability(P)(at least 2heads)= 4/8=½

P(at least 2 heads)= ½

Hence, the probability of getting at least 2 heads= ½.

HOPE THIS WILL HELP YOU..

Answer 2

Answer:

Step-by-step explanation:

S=(TTT, THT, HHH, THH, HTT

, HHT, TTH, HTH)

Therefore, n(S) =8

Let A be the event of getting at least two tails

A=(TTT, THT, HTT, TTH)

Therefore n(A) =4

P(A)=n(A)/n(S)

= 4/8

=1/2