when three consecutive even integers are added the sum is 0 find the integer
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let first even no be x
then the second consecutive even no be x+2,
and third even no be x+4 respectively
ACCORDING TO THE QUESTION
SUM OF THESE CONSECUTIVE EVEN =0
x+2+x+4+x=0
3x+6=0
3x=-6
x=-6/3
x=-2
so the three consecutive integers will be -2,0,2
then the second consecutive even no be x+2,
and third even no be x+4 respectively
ACCORDING TO THE QUESTION
SUM OF THESE CONSECUTIVE EVEN =0
x+2+x+4+x=0
3x+6=0
3x=-6
x=-6/3
x=-2
so the three consecutive integers will be -2,0,2
ojili66pc0onq:
we should divide -2 by 4 to get third integer 2
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