Question

when three consecutive even integers are added the sum is zero find the integers

Answer 1

Step-by-step explanation:

let a be the first term

second term = a+1

third term =a+2

sum =0

a+a+1+a+2 =0

3a +3 = 0

a+1 =0

a = -1

therefore integer are

a = -1

a+1 = o

a+2 = 1

hope so helpful and correct !!!!!!!!!!!!!!!!!!!!!

Answer 2

$let \: first \: integer \: = x \\ second \: integer \: = x + 2 \\ third \: integer \: = x + 4 \\ according \: to \: question \: \\ x + x + 2 + x + 4 = 0 \\ 3x + 6 = 0 \\ 3x = - 6 \\ x = \frac{ - 6}{3} \\ x = - 2 \\ so \: first \: no. \: = - 2 \\ second \: no \: = - 2 + 2 = 0 \\ third \: no. \: = - 2 + 4 = 2$