Question

when three consecutive even integers are added the sym is zero . find the integers.

Answer 1

I can definitely say there exist no such positive even integers, Whose sum is 0,

If you think negative integers are also classified as even and odd, Then the solution is,

Let three consecutive even integers be 
X-2, X, X+2,

according to data, their sum is 0,

(X-2) + (X) + (X+2) = 0,

3X = 0,

X = 0, 
Now the three integers are -2, 0, +2 !!

Hope This Helps :)

Answer 2

Let the integers be a, a+2,a+4

According to question

a +a +2+a+4 = 0

=> 3a +6 = 0

=> 3a = - 6

=> a = - 2

First integer = - 2

Second integer = 0

Third integer = 2