Question

When three consecutive natural numbers are add, the sum is 21. find the numbers.​

Answer 1

Answer:

Let one number be x.

Then, the other number will be x+2.

The third number = x+2+2=x+4

It is given that their sum is 21.

So, x+(x+2)+(x+4)=21

3x+6=21

3x=15

x=5

and x+2=7

x+4=9.

Answer 2

Step-by-step explanation:

ANSWER

let the numbers be X, x+1,x+2

x+x+1+x+2=21

3x+3=21

3x=21-3

3x=19

x=19/3

so the numbers are 19/3,19/3+1,19/3+2

solve from 19/3+1 and 19/3+2

you will get your answer

hope this helps