when three consecutive odd integers all added the sum is - 1 find the integer
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Solution:
Let x - first consecutive odd integer
x + 2 - second consecutive odd integer
x + 4 - third consecutive odd integer
(x) + (x + 2) + (x + 4) = -1
x + x + 2 + x + 4 = -1
3x + 6 = -1
3x = -1 - 6
3x = -7
x = -7/3
Therefore, x = -7/3 - 1st
-7/3 + 2 = -1/3 - 2nd
-7/3 + 4 = 5/3
(-7/3) + (-1/3) + (5/3) = (-8 +5)/3 = -3/3 = -1
Hope this will be helpful to you.
Let x - first consecutive odd integer
x + 2 - second consecutive odd integer
x + 4 - third consecutive odd integer
(x) + (x + 2) + (x + 4) = -1
x + x + 2 + x + 4 = -1
3x + 6 = -1
3x = -1 - 6
3x = -7
x = -7/3
Therefore, x = -7/3 - 1st
-7/3 + 2 = -1/3 - 2nd
-7/3 + 4 = 5/3
(-7/3) + (-1/3) + (5/3) = (-8 +5)/3 = -3/3 = -1
Hope this will be helpful to you.
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