When three identical bulbs of 60 watt, 200 volt rating are connected in series to a 200 volt supply, the power drawn by them will be :-
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Answer:
20W.
Explanation:
Bulb Watt = 60 (Given)
Voltage of the bulb = 200V (Given)
Supply series = 200 (Given)
Resistance of each bulb = (V²/P)
= (200²/60)
= 666.67 ohms.
When three bulbs are connected in series their resultant resistance -
Current flowing through 3 in series I = (E/R) = 200/(3 x 666.7) = 0.1A.
Thus, the power drawn by bulb when connected across 200 V supply -
Power each bulb dissipates = (200/3) x 0.1
= 6.67 Watts.
By all 3 bulbs = 20W
Thus, the power drawn by three bulbs will be 20W.
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