Question

When three identical bulbs of 60W, 200 V rating are connected in series to a 200 V supply, the power drawn by them will be
1) 60W
2) 180W
4) 10W
3) 20W​

Answer 1

Answer:the resistance of each bulb

=v^2/p

=(200)^2 /60

=when three bulb are connected in series their resistance

3 x (200)2/6

Thus power drawn by bulb when connected across 200v supply

P=V^2 /Rre = (200)^2 /3x(200)^2/60

= 20 (ans )