Physics, asked by sanketmohapatra06, 1 day ago

When three resistors are connected in series with a battery of voltage V and voltage
drop across resistors is V1, V2 and V3, Which of the relation is correct ?

(a) V=V1=V2=V3
(b) V=V1+V2+V3
(c) V1+V2+V3=3V
(d) V> V1+V2+V3

Answers

Answered by kajalgargdei
11

Answer:

(b) V = V_1 + V_2 + V_3

Explanation:

when three resistors are connected in series the equivalent resistance R will be

R = R_1 + R_2 + R_3\\R = V/I\\V/I = V_1 /I + V_2 /I+ V_3/I\\\\V = V_1 + V_2 + V_3\\

Answered by Syamkumarr
9

Answer:

The correct answer is  (b) V = V₁ +V₂ +V₃

Step-by-step explanation:

Given that  

Three resistors are connected in series with a battery of voltage V

drop across resistor is V₁, V₂,  and V₃

Resistor

  • Resistor is a two terminal electrical component which regulates current flow, when if there is any high or low voltage of current flow  within a circuit
  • The resistance in a circuit (R) is inversely proportional to the current (I) in the circuit

                    ⇒ R ∝ \frac{1}{I}    ⇒  R = \frac{V}{I}  ⇒  V = IR  [ where V is voltage ]

Resistors series combination  

  • In series combination of Resistors, Resistors are connected one after another in a sequence manner, here the current flow in each resistor is same
  • The equivalent resistance in circuit is equals to sum of the all resistors  
  • From given data 3 resistors are connected in a series combination                  

        let R₁ , R₂ and  R₃ be the connected resistors

     ⇒   the equivalent Resistance R =  R₁ + R₂ + R₃

                                ⇒   R = \frac{V_{1} }{I} + \frac{V_{2} }{I} + \frac{V_{3} }{I}  

                                ⇒   R = \frac{V_{1} + V_{2} + V _{3}  }{I}  

                                ⇒   IR = V₁ + V₂ + V₃

                                ⇒   V = V₁ + V₂ + V₃  

Therefore the correct relation from options  is (b)   V =V₁ + V₂ +V₃

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