When three unbaised coins are thrown, the probability of getting exactly two tails and probability of getting at least two tails are the roots of a Quadratic equation.Find the Quadratic equation.
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n(s)={H,T} x {H,T} x {H,T}
={H,H,H},{H,H,T},{H,T,H},{H,T,T}{T,H,H},{T,H,T},{T,T,H},{T,T,T}=8
now events of exactly getting two tails
n(E)={H,T,T},{T,H,T},{T,T,H}
=3
now,
p(E)=n(E)/n(s)=3/8
again events of getting at least two tails
n(E)={H,T,T},{T,H,T},{T,T,H},{T,T,T}=4
now ,
p(E)=n(E)/n(s)=4/8
according to question ,
3/8 and 4/8 are the roots of quadratic
hence, quadratic equation :-
(x-3/8)(x-4/8)=0
x^2-7x/8+12/64=0
64x^2-56x+12=0
hence 64x^2-56x +12=0. is quadratic equation.
={H,H,H},{H,H,T},{H,T,H},{H,T,T}{T,H,H},{T,H,T},{T,T,H},{T,T,T}=8
now events of exactly getting two tails
n(E)={H,T,T},{T,H,T},{T,T,H}
=3
now,
p(E)=n(E)/n(s)=3/8
again events of getting at least two tails
n(E)={H,T,T},{T,H,T},{T,T,H},{T,T,T}=4
now ,
p(E)=n(E)/n(s)=4/8
according to question ,
3/8 and 4/8 are the roots of quadratic
hence, quadratic equation :-
(x-3/8)(x-4/8)=0
x^2-7x/8+12/64=0
64x^2-56x+12=0
hence 64x^2-56x +12=0. is quadratic equation.
mysticd:
nice work
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