Question

When three unbiased coins are tossed together, what is the probability of not getting two tails and one head in any order? ​

Answer 1

GiVEN

• 3 unbiased coins are tossed together

TO FiND

• Probability of Not getting two tails and one head

SOLUTiON

• T = tails
• H = head

• S = { TTT, TTH, THH, THT, HHH, HHT, HTT, HTH }
• n(S) = 8

• Let A be the event of not getting two tails and one head in any order

• A = { TTT, THH, HHH, HHT, HTH }
• n(A) = 5

• P(A) = n(A) / n(S) = 5/8

★ Thus, probability of not getting two tails and one head is 5/8.

Answer 2

Answer:

(i) at least two tails

Then E=4

So (p)= n(E) /n(S)

=  4/8= 1/2

(b) (ii) at most two tails

Then E=7

So (p)= n(E) /n(S) ​= 7/8

(iii) At most two heads

Then E=7

So (p)= n(E)/ n(S) = 7/ 8

​ please mark me the brainliest...

Explanation: