Physics, asked by leothomasalves, 9 months ago

When transistors are used in digital circuits they usually operate in the,

Answers

Answered by shaheenfarooqui1234
0

Answer:

Answer:− D

Transistor in Cutoff/Saturation Mode - Digital Electronics

When both the pn junctions of a transistor is reversed biased we say the transistor is in cut off mode.

When base-emitter junction is forward biased and base-collector junction is reverse biased we say the transistor is in operating in Active mode.

When both the pn junctions are forward biased we say transistor is operating in saturation mode.

Saturation Mode

     I  

c

​  

>I  

c

​  

(max)

     I  

c

​  

(max)=  

R  

c

​  

 

V  

cc

​  

 

​  

 

     I  

c

​  

=βI  

b

​  

 

     I  

c

​  

=I  

c

​  

(max)

     V  

c

​  

=I  

c

​  

×R  

c

​  

=V  

cc

​  

 

     V  

o

​  

=V  

cc

​  

−V  

c

​  

=0V

Active Mode

      0<I  

c

​  

<I  

c

​  

(max)

      I  

b

​  

=  

R  

b

​  

 

(V  

b

​  

−V  

be

​  

)

​  

 

      I  

c

​  

=β×I  

b

​  

 

      V  

c

​  

=I  

c

​  

×R  

c

​  

 

      V  

o

​  

=V  

cc

​  

−V  

c

​  

 

      0V<V  

o

​  

<V  

cc

​  

 

     

Cut off region

      V  

b

​  

<V  

be

​  

  (Generally 0.7V)

So, I  

b

​  

=0A

      I  

c

​  

=0A

      V  

c

​  

=I  

c

​  

×R  

c

​  

=0V

      V  

ce

​  

=V  

o

​  

=V  

cc

​  

−V  

c

​  

=V  

cc

​  

 

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