When two capacitors are joined in series the resultance capacity is 2.4F and when the same two are
joined in parallel the resultant
capacity is 10F . Their individual capacities are
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Answered by
2
Answer:
4F and 6F
Explanation:
let the capacitances be x and y
given 1/x + 1/y = 1/2.4 = 5/12
i e xy/(x+y) = 12/5
and x+y = 10
therefore xy = 24
from these last 2 equations, we get x and y as 4 and 6
Answered by
2
Explanation:
let c1 and c2 be the capicitors
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