Question

When two cells of e.m.f.s 1.5V and 1.1V connected in series are balanced on a potentiometer , the balancing length is 260 cm . The balancing length when they are connected in opposition is(in cm)

Answer 1

Answer:

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Answer 2

The balance length is 40 cm.

Explanation:

Given that,

e.m.f of first cell = 1.5 V

e.m.f of second cell = 1.1 V

Length = 260 cm

We need to calculate the balance length

Using relation of emf and length

$\dfrac{e_{1}+e_{2}}{e_{1}-e_{2}}=\dfrac{l_{1}}{l_{2}}$

Put the value into the formula

$\dfrac{1.5+1.1}{1.5-1.1}=\dfrac{260}{l_{2}}$

$l_{2}=\dfrac{260}{6.5}$

$l_{2}=40\ cm$

Hence, The balance length is 40 cm.

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