Question

When two charges 5c and 20c are
separated by 10m, force b/w them will be
a) 10N b) 9x10°N
b) 9x10°N c) 100N d) ON​

Answer 1

Explanation:

Force b/w them can be calculated using columbs law....

F=

$\frac{kq1q1}{ {r}^{2} }$

where r is distance between them and k=

$9 \times {10}^{9}$

F=

$9 \times {10}^{9} \times 5 \times 20 \div {10}^{2}$

=

$9 \times {10}^{9} newton$