When two chocolate coloured Labradors were crossed, a yellow puppy was born, what is the probability of yellow coat coloured puppy if the parents are again crossed?
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15
Answer:
this is 1:4 !)) there woulb be a chance of one yellow puppy due to yellow gene
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Explanation:
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10
Probability of yellow coat colored puppy = 1/4.
- It represents a monohybrid cross (representing a single trait) for coat color.
- Chocolate color coat color phenotype is expressed by the presence of dominant allele - "A", therefore the phenotypes of chocolate coat color are - Aa (heterozygous individual) or AA (homozygous dominant individual), and yellow coat color is being expressed in individuals having a pair of recessive alleles "aa" (homozygous recessive individual).
- The birth of a yellow puppy signifies the presence of a recessive allele in both the parents as a single allele for a particular trait (coat color) is received from each parent by the offspring. Hence both the parents have the heterozygous genotype for the Chocolate coat color of Labradors.
- ∴ Aa × Aa (Parents)
- Aa, Aa, AA, aa (offsprings)
- Total number of offspring that can be formed by heterozygous parents cross = 4
- Number of a yellow or recessive homozygous individual - "aa"= 1
- probability of yellow coat colored puppy = 1/4
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