Question

when two coins are tossed at once then the probability of getting at most one head is 3/4.​

Answer 1

Step-by-step explanation:

On tossing two coins sample space

S = {HH, HT, TH, TT}

Therefore n(S) = 4

Let A be the event of getting at most two heads

So, A = {HH, HT, TH, TT}

Hence, n(A) =4

$\therefore \: P(A) = \frac{n(A)}{n(S)} = \frac{4}{4} = 1$

Answer 2

Answer:

when two coins are tossed

the outcomes are

HH,HT,TH,TT

therefore the total outcomes is4

the probability of getting at most one head is 3/4