Question

When two coins are tossed simultaneously, what is the probability of getting:
1) atleast one head
2) exactly two tails
3) one head & one tail​

Answer 1

Answer:

Let E9 = event of getting 1 head and 1 tail. Then, E9 = {HT, TH } and, therefore, n(E9) = 2. Therefore, P(getting 1 head and 1 tail) = P(E9) = n(E9)/n(S)= 2/4 = 1/2.