Question

When two concurrent forces 20kg and 15 kg act at right angles on a particle, then their resultant will be equal to?

Answer 1

Given:

• Two concurrent forces 20kgf and 15 kgf act at right angles on a particle.

To find:

• Resultant on the particle?

Calculation:

Since the forces are acting at 90°, we have to apply VECTOR ADDITION for the forces.

• Let resultant be R :

$R = \sqrt{ {15}^{2} + {20}^{2} + 2.15.20. \cos( {90}^{ \circ} ) }$

$\implies R = \sqrt{ {15}^{2} + {20}^{2} + 2.15.20.(0) }$

$\implies R = \sqrt{ {15}^{2} + {20}^{2} }$

$\implies R = \sqrt{ 225 + 400 }$

$\implies R = \sqrt{ 625 }$

$\implies R = 25 \: kgf$

So, the net force on the particle is 25 kgf.