When two dice are rolled find the probability of getting a sum that is divisible by 4?
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n(S)=36
let A be the event that getting sum is divisible by 4. Hence possible values are
1,3
2,2
2,6
3,1
3,5
4,4
5,3
6,2
6,6
Hence n(A)=9
P(A) = n(A)/n(S)=9/36=1/4
let A be the event that getting sum is divisible by 4. Hence possible values are
1,3
2,2
2,6
3,1
3,5
4,4
5,3
6,2
6,6
Hence n(A)=9
P(A) = n(A)/n(S)=9/36=1/4
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