Question

When two dice are thrown together then find the prplopabiliylty of getti g prime no?

Answer 1

Let A be event of getting a prime number

n(A)=6 (2,3,5,2,3,5)-Two dice

Total number of faces

n(s)=12 (1,2,3,4,5,6,1,2,3,4,5,6)-Two dice

Probability

P(A)=n(A)/n(S)=6/12 or 1/2

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Answer 2

Answer:

when two dice are thrown

S= {{1,1) (1,2),(1,3,),(1,4),(1,5),(1,6)

(2,1)(2,2) (2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3.3)(3.4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)5,3)(5,4)(5,5) (5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}

n(S)=36

Getting prime number on both dice =(2,2) (2,3) (2,5),(3,2) (3,3) (3,5)(5,2) (5,3) (5,5)

Required probability =9/36 = 1/4

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