Question

When two Dice are thtown what is the probability of getting :

1) Doublet
2) 1 on first dice
3) Even number on 2nd and odd on 1st dice
4) Odd on both dice
5) Sum is either 9 or 11
6) Sum is a prime number
7) Sum is 15
8) No. divisible by 3 on 2nd dice
9) Sum is divisible by 4
10) Sum as multiple of 7
11) Sum as even number
12) Product as 6
13) Product divisible by 9
14) Product as prime number
15) Even Product

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Answer 1

1. 1/6

2. 1/18

3. 1/4

4. 1/4

5. sum is 9 : 1/9 , sum is 11 : 1/18

6. 13/36

7. 0/36

8. 1/3

9. 1/4

10. 1/6

11. 1/2

12. 1/9

13. 1/9

14. 1/12

15. 3/4

Answer 2

Step-by-step explanation:

1) 6/36= 1/6

2) 6/36=1/6

3) 9/36

4) 9/36

5) 1/6

6) 5/12

7) 0

8) 12/36=1/3

9) 9/36=1/4

10) 6/36= 1/6

11) 18/36=1/2

12) 4/36= 1/9

13) 1/9

14) 1/6

15) 27/36= 3/4

I hope is helps