When two Dice are thtown what is the probability of getting :
1) Doublet
2) 1 on first dice
3) Even number on 2nd and odd on 1st dice
4) Odd on both dice
5) Sum is either 9 or 11
6) Sum is a prime number
7) Sum is 15
8) No. divisible by 3 on 2nd dice
9) Sum is divisible by 4
10) Sum as multiple of 7
11) Sum as even number
12) Product as 6
13) Product divisible by 9
14) Product as prime number
15) Even Product
only @stutiAggarwal will answer....plz
Answers
Answered by
17
Step-by-step explanation:
1) 6/36
2) 6/36
3)9/36
4) 9/36
5) 1/6
6) 5/12
7) 0
8) 12/36
9) 9/36
10)6/36
11) 18/36
12) 4/36
13) 1/9
14) 1/6
15) 27/36
Answered by
1
1) 6/36
2) 6/36
3)9/36
4) 9/36
5) 1/6
6) 5/12
7) 0
8) 12/36
9) 9/36
10)6/36
11) 18/36
12) 4/36
13) 1/9
14) 1/6
15) 27/36
Similar questions