Question

When two dice are tossed, probability of getting
six as uppermost face on both the die is​

Answer 1

Answer:

The favorable possibilities are below such that product is divisible by 6

(1,6) (2,3) (2,6) (3,2) (3,4) (3,6) (4,3) (4,6) (5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6) = 15 ways

Total ways = 6 x 6 = 36 ways

Probability - 15/36 = 5/12

Hope this answer was useful.

Answer 2

Probability of getting six as uppermost face on both the dice is 1/36  if two dice are tossed

Given:

• Two Dice are tossed

To Find:

• Probability of getting six as uppermost face on both the dice

Solution:

• Probability of an event  = n(E)/n(S)  
• n(E) = number of possible outcome of event
• n(S) = number of possible sample space outcome

Step 1:

Dice has 1 to 6 numbers  Hence total possible outcomes of 1 dice are 6

and Possible outcomes of 2 dice are

6 x 6 = 36

Step 2:

Favorable case to get 6 on uppermost face on both the  dice is 1 only

(6 , 6)

Step 3:

Find the Probability of getting six as uppermost face on both the dice

= 1/36

Hence, probability of getting six as uppermost face on both the dice is 1/36  if two dice are tossed