Question

when two dice are tossed together, find the probability that the sum of number on their tops is less than 7. ​

Answer 1

Answer:

Either you can write all the 36 outcomes and count the number of outcomes whose sum is 7.

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Bolded ones are favourable outcomes.

or

You just have to found for which values x+y=7,wherex,y=1,2,3,4,5or6

just find out all possibilities and chose the favourable one.

I Hope It Will Help!

^_^

Answer 2

Answer:

5/12

Step-by-step explanation:

n(s)=36

n(a)=15

p(a)=15/36=5/12