Question

when two dies are thrown simuntaneously
what is the probability og getting sum of 11​

Answer 1

Answer:

1/12

Step-by-step explanation:

The total number of possibilities is 6 for the first die and 6 for the second. Since each throw on the first die could be paired with any of the six on the second, the total ways the dice could fall is 6 × 6 = 36.

So,probability of getting 11 = 3/36

= 1/12

Answer 2

Answer:

1/13

Step-by-step explanation:

total no. of outcomes=36

{ 1,1 ; 1,2 ; 1,3 ; 1,4 ; 1,5 ; 1,6 ;

2,1 ; 2,2 ; 2,3 ; 2,4 ; 2,5 ; 2,6 ;

3,1 ; 3,2 ; 3,3 ; 3,4 ; 3,5 ; 3,6 ;

4,1 ; 4,2 ; 4,3 ; 4,4 ; 4,5 ; 4,6 ;

5,1 ; 5,2 ; 5,3 ;  5,4 ; 5,5 ; 5,6 ;

6,1 ; 6,2 ; 6,3 ; 6,4 ; 6,5 ; 6,6 }

total no. of favourable outcomes=2(5,6 ;6,5)

probability =no. of favourable outcoms/total no. of outcomes

                  = 2/36

                  =1/13