when two electrons are transferred from one conductor to another potential differnce of 20 v exists between calculate the capacitance of two conductor systems
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Charge on each conductor = Q = 2 e = 2 * 1.6 *10^-19 Coul
V = potential difference = 20 Volts
Capacitor of the two conductor system = Q/V = 1.6 * 10^-20 Farad
V = potential difference = 20 Volts
Capacitor of the two conductor system = Q/V = 1.6 * 10^-20 Farad
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