When two equations x^2+a1x+b1=0 and x^2+a2x+b2=0 have equal root (x-k) then find k?
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x2+a1x+b1=0------------eq(1)
x2+a2x+b2=0-------------eq(2)
equal root x-k=0 => x=k is one root
f(k) in eq (1) and eq(2)
k2+a1k+b1=k2+a2k+b2
k(a1-a2)=b2-b1
k=(b2-b1)/(a1-a2)
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