when two forces of 50N and 35N acts in opposite direction on boxc
calculate the net resulant force
Answers
Answer:
Answer: The magnitude of the forces are 40N and 30N
Solution:
The blocks in contact with respective forces show resultant force as 10 N when opposite and 50 N when perpendicular, so the respective force is calculated as following,
Given: Resultant force when opposite = 10 N
Resultant force when perpendicular = 50 N
Let the first force be F1 and second force be F2
So when F1 and F2 are opposite, resultant force is given by F1 – F2 = 10 N
F1 = 10 + F2
And when F1 and F2 are perpendicular, the resultant force is given by –
\begin{gathered}\begin{array}{l}{\sqrt{F 1^{2}+F 2^{2}}=50 N} \\ {\sqrt{(10+F 2)^{2}+F 2^{2}}=50 N} \\ {\sqrt{10^{2}+F 2^{2}+2 F 2+F 2^{2}}=50 N} \\ {100+2 F 2^{2}+2 F 2=2500}\end{array}\end{gathered}
F1
2
+F2
2
=50N
(10+F2)
2
+F2
2
=50N
10
2
+F2
2
+2F2+F2
2
=50N
100+2F2
2
+2F2=2500
\begin{gathered}\begin{array}{l}{2 F 2^{2}+2 F 2=2500-100} \\ {2 F 2^{2}+2 F 2-2400=0} \\ {F 2^{2}+F 2-1200=0}\end{array}\end{gathered}
2F2
2
+2F2=2500−100
2F2
2
+2F2−2400=0
F2
2
+F2−1200=0
On solving this equation we get F2 = 30 N
Therefore F1 = 10 + F2
F1 = 10 + 30 = 40 N
Therefore, the two forces are 40 N and 30 N respectively
Answer:
15N
Explanation:
When two forces act in opposite direction, both the forces are subtracted to obtain the net force.
Therefore, net force in this case is 50N-35N= 15N
I hope it helps you.