When two identical resistors are connected in series across ideal battery, total power dissipated by them is P. Now both are connected in parallel and same battery is connected across the combination. Now find the total power dissipated by both of them.
Answers
4P is the total power dissipated by both of them
Explanation:
Let say Voltage of Battery = V
Resistance of Each Resistor = R
Connected in Series Hence Total Resistance = R + R = 2R
total power dissipated by them = V²/2R
=> P = V²/2R
Now both are connected in parallel
Hence Net Resistance = 1/(1/R + 1/R) = R/2
Power Dissipated = V²/(R/2)
= 2V²/R
= 2 * 2 V²/2R
= 4 * V²/2R
= 4P
total power dissipated by both of them. = 4P
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Answer:
4P
Explanation:
In series, the total resistance of the circuit would increase, which would result is less current
Power Formula = V^2/ R
Incase of series circuit, the net resistance of two identical resistors having R resistance would be 2R. The power would be;
Power Formula = V^2/ 2R
Now when we connect them in parallel, the net resistance would be get half R and then in this case.
Power = V^2/ R/2
Power = 4P
Hence this time, the power would be four times than the actual one